time up equals time down ... so the ball takes (6.36 s / 2) to travel up (or down)
distance = 1/2 g t^2 = 1/2 * 9.81 m/s^2 * (6.36 s / 2)^2
During a baseball game, a batter hits a high
pop-up.
If the ball remains in the air for 6.36 s, how
high does it rise? The acceleration of gravity
is 9.8 m/s
2
.
Answer in units of m.
3 answers
if yalll didnt understand, here also b/c why not
vf-vi=at, so find that negative number then divide by two and it will give u |vi|
make it positive
vf =0 at the top, so
0^2=vi^2 + 2a ∆x
then
-(vi^2)/(2a){should be 19.6}= ∆x
vf-vi=at, so find that negative number then divide by two and it will give u |vi|
make it positive
vf =0 at the top, so
0^2=vi^2 + 2a ∆x
then
-(vi^2)/(2a){should be 19.6}= ∆x
24
1 answer