During a baseball game, a batter hits a high pop-up.

Question

If the ball remains in the air for 6.41 s, how
high above the point where it hits the bat
does it rise? Assume when it hits the ground
it hits at exactly the level of the bat.
acceleration of gravity is 9.8 m/s

Answer 1

During a baseball game, a batter hits a high pop-up.
If the ball remains in the air for 6.41 s, how
high above the point where it hits the bat
does it rise? Assume when it hits the ground
it hits at exactly the level of the bat.
acceleration of gravity is 9.8 m/s
can someones pls help im currently doing the timed homework

Answer 2

time up equals time down

d = 1/2 * g * (6.41 / 2)^2

your g number is two sig fig ... so your answer should be also