I will be happy to critique your work. To solve for x, combine the terms that include x on one side and the constants on the other.
"Combining" like terms" means separately combining the terms with different powers of x, and the constants.
Combine like terms:
-3x^2+2x-4x^2-9+6x-2x^2+8
Solve for x:
8x-11= -11x+18
Solve for x:
-2(x-5)+7=z-8-5x
Solve for x:
(x-2)/5 - 3/2= (x+1)/10
Translate to an algebra statement; do not solve:
Seven times the difference of six and a twice a number yields the same result as the same number decreased by one.
8 answers
Seven times the difference of six and a twice a number yields the same result as the same number decreased by one.
How does this translate into a algebra statement?
How does this translate into a algebra statement?
I can answer 3x^2+2x-4x^2-9+6x-2x^2+8
first you want to combined all the squared problems whch is : 3x^2 -4x^2-2x^2
Since two negatives make a positive : 3x^2-4x^2 =7x^2
now subtract -2x^2 and that leaves for 5x^2
Now you combine all the numbers with variables : 2x +6x = 8x
so now we have
5x^2+ 8x
now we combine all the constant numbers -9+8= -1
answer 5x^2+8x -1
first you want to combined all the squared problems whch is : 3x^2 -4x^2-2x^2
Since two negatives make a positive : 3x^2-4x^2 =7x^2
now subtract -2x^2 and that leaves for 5x^2
Now you combine all the numbers with variables : 2x +6x = 8x
so now we have
5x^2+ 8x
now we combine all the constant numbers -9+8= -1
answer 5x^2+8x -1
7(6-x2) = x2-1
Seven times the difference of six and a twice a number yields the same result as the same number decreased by one.
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The ratio of 7 more than a number to 2 less than that number is 13/4. Find the number
seven less than twice an unknown number