At the end of Summer, Puss discovers that his radiator antifreeze

At the end of Summer, Puss discovers that his radiator antifreeze solution has dropped below the safe level. If the radiator contains 4 gallons of a 25% antifreeze solution, how many gallons of pure antifreeze must he add to bring it up to a desired 50% solution? how to solve this and please solution

21 answers

Let the amount of old stuff drained by x gallons
so you have 4-x gallons left of 25% solution

.25(4-x) + x = .5(4)
1 - .25x + x = 2
.75x = 1
(3/4)x = 1
x = 4/3

so drain 4/3 gallon of the current solution, then top it up with pure antifreeze

thanks you sooooooooooo much!

i do not think that the answer to this question is 4/3 the quoins asks

how many gallons of pure antifreeze must he add to bring it up to a desired 50% solution?

can someone please find the right answer plz plz plz

The new capacity is 4+x=y
Where x is the pure anti-freeze,
y is the total capacity.

4+x=y
0.25(4)+x=0.5y

1+x=2+0.5x
x=2

He needs to add 2 gallons of pure anti-freeze.

thanks

NO THE RIGHT ANSWER IS 69 OR 420

No 2 gallons is the correct answer.

Idk pls help

No, its 2

its 2.

The answer is 2

its 2

its 2 :)

it's right genius answer right there

The correct answer is definitely 2. John is absolutely correct.

I'm giving everyone who said 2 gallons a thumbs up!!! correct!!!

Yep 2 gallons is 100% correct

fjkdfjdfsndkfjahdskfhdksjhfkdsajfhsdkhfsdjkfhdsk

It has to be 2

Dude the answer is 2 bro