presently is
.6 * 3.6 = 2.16 af
.4 * 3.6 = 1.44 h2o
should be
.5 * 3.6 = 1.8 af
1.8 h2o
add x liters water
take out .6 x af and .4 x water
new af = 1.8 = 2.16 - .6 x
so
.6 x = .36
x = .6
==============
check
new water = 1.44 - .4(.6) + .6
= 1.8 whew
The radiator in a car is filled with a solution of 60% antifreeze and 40% water. The manufacturer of the the antifreeze suggests that, for summer diving, optimal cooling of the engine is obtained with only 50% antifreeze. If the capacity of the radiator is 3.6 liters, how much coolant should be drained and replaced with waterto reduce antifreeze concentration to the recommended level.
1 answer
1 answer