centripetal acceleration is v^2/r
The tension in the chain is m*v^2/r
where v is the speed = 2*PI*r*f
where f is the frequency; r is the radius; m is the mass
v = 2*PI*1.2*0.432
solve for the acceleration and tension using the above equations
An athlete whirls a 6.6 kg hammer tied to
the end of a 1.2 m chain in a horizontal circle.
The hammer moves at the rate of 0.432 rev/s.
What is the centripetal acceleration of the
hammer? Assume his arm length is included
in the length given for the chain.
Answer in units of m/s
2
What is the tension in the chain?
Answer in units of N
1 answer
3 answers