An athlete whirls a 7.00 kg hammer tied to the end of a 1.1 m chain in a horizontal circle. The hammer makes one revolution in 0.9 s. What is the tension in the chain?

Answer 1

The speed of the hammer must be
V = 2 pi*1.1/0.9 = 7.68 m/s. The chain cannot not be quite horizontal, but tipped at an angle A (to support the weight) so that
M V^2/R = T cos A and
M g = T sin A
tan A = g R/V^2 = 0.183
which means that
A = 10.3 degrees
T = (M V^2/R)/cos10.3 = ______

If you do not include the cos 10.5 factor, your answer will be about 2% off.

Answer 2

This is the wrong answer, do not copy it

Answer 3

396 (approx)

Answer 4

396 N (approx)

Answer 5

A single electron is placed in an electric field where the intensity 103.5 N/c. What force does the electron experience?