An athlete whirls a 7.50-kg hammer tied to the end of a 1.1-m chain in a horizontal circle. The hammer moves at the rate of 1.3 rev/s.(a) What is the centripetal acceleration of the hammer?(b) What is the tension in the chain?

Answer 1

acceleration= w^2 r= (1.3*2PI rad/sec)^2 1.1m

tension= masshammer*acceleration

Answer 2

Acctually i just found the answer for the acceleration, its similar to what you said except that you don't square it.The tension is (mass)(acceleration).

Answer 3

well, it is nice to know I have been doing it wrong, apparently, for 50 years.

I see here in Canada they are doing it my way also. Well, they are Canadians.

http://theory.uwinnipeg.ca/physics/circ/node6.html

Answer 4

Could it be that I've been doing it wrong for the past 40+ years too, unless of course there is a not-so-minute chance that the textbook answer is wrong?

Answer 5

no its just that this is in revolutions per second (goes around the whole circle) when it should be redious per second. most questions just give it in seconds so it would be correct the other way (unless of course it is given in revolutions per second like in this problem).