F= ma. F= ma
m= 3.41×10^4kg. m= 89kg
F= 3.58 × 10^4N. a =1.05m/s^2
from F= ma. F= 89×1.05
3.58 × 10^ 4= 3.41 × 10^4a. = 93.45N
a= 1.05m/s^2
An airplane has a mass of 3.41 × 104 kg and takes off under the influence of a constant net force of 3.58 × 104 N. What is the net force that acts on the plane's 89.0-kg pilot?
2 answers
Mplane = 34100kg
Fnet= 35800N
Mpilot = 89kg
Note: The net force of on the pilot from the plane=0..(Non-inertia). The net force from the ground before takeoff can be calculated below:
Fnet = ma
a = Fnet/Mplane; a = 35800N/34100kg....a =1.05m/s/s.
Fpilot =Mpilot (a); Fpilot = 89kg (1.05m/s/s)= 93.45N.
Therefore, the net force (Fnet) acting on the pilot is 93.45N.
Fnet= 35800N
Mpilot = 89kg
Note: The net force of on the pilot from the plane=0..(Non-inertia). The net force from the ground before takeoff can be calculated below:
Fnet = ma
a = Fnet/Mplane; a = 35800N/34100kg....a =1.05m/s/s.
Fpilot =Mpilot (a); Fpilot = 89kg (1.05m/s/s)= 93.45N.
Therefore, the net force (Fnet) acting on the pilot is 93.45N.
1 answer