Asked by Shanti
an aeroplane is travelling horizontally at a speed of 80ms and drops a crate of emergency supplies.To avoid damage,the max vertical speed of the crate on landing is 20ms.
a)calc d max height of the aeroplane when the crate is dropped
b)calc d time taken for the crate to reach the ground from this height.
a)calc d max height of the aeroplane when the crate is dropped
b)calc d time taken for the crate to reach the ground from this height.
Answers
Answered by
Steve
v = at
20 = 9.8 t
t = 2.04s
so, it can't fall for more than 2.04 seconds, or it will be going too fast
so, how far will it fall in 2.04 s?
s = 1/2 at^2
s = 4.9 * 4.16
s = 20.38m
Man, that's some low flyer!
20 = 9.8 t
t = 2.04s
so, it can't fall for more than 2.04 seconds, or it will be going too fast
so, how far will it fall in 2.04 s?
s = 1/2 at^2
s = 4.9 * 4.16
s = 20.38m
Man, that's some low flyer!
Answered by
anonymous
Shouldn't we like need to find the total velocity first since horizontal speed is 80m/s and vertical speed is 20m/s?
Answered by
M1000
Very helpful
Answered by
Hannah
Thank you very much. this was very helpful.
Answered by
Chris
Using V2 = U2 + 2gh
U=0
V2 = 2gh
h = V2/2g
h = 400/19.62
h = 20.39m
U=0
V2 = 2gh
h = V2/2g
h = 400/19.62
h = 20.39m
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