An aeroplane is travelling horizontally at a speed of 80ms and drops a crate of emergency supplies.To avoid damage,the maximum vertical speed of the crate on landing is 20ms.

Question

a)the aeroplane is travelling at the maximum permitted height.Calc the horizontal distance travelled by the crate after it is released from the aeroplane.

Answer 1

given the speed of 20 m/s

vf^2=2gh
h=20^2/2*9.8= 200/9.8 m

time in air:
hf=hi-4.9t^2
t= sqrt(200/(9.8*4.9))

horizontal distance
distance= 80m/s*timeinairabove