According to the Law of Conservation of Mass, if 88 g of carbon dioxide ( CO2

Question

) is produced in a reaction between oxygen (O) and 24 g of carbon (C), what is the mass of dioxygen ( O2
) in the reactants?(1 point)
Responses

32 g
32 g

24 g
24 g

64 g
64 g

104 g

Answer 1

According to the Law of Conservation of Mass, the total mass of the reactants must equal the total mass of the products in a chemical reaction.

In this case, we know that:

• The mass of carbon (C) is 24 g.
• The mass of carbon dioxide (CO₂) produced is 88 g.

To find the mass of dioxygen (O₂) in the reactants, we can use the following equation:

Total mass of reactants = Total mass of products

Let \( m \) be the mass of O₂:

\[ m + 24 \text{ g (mass of C)} = 88 \text{ g (mass of CO₂)} \]

Now, solving for \( m \):

\[ m = 88 \text{ g} - 24 \text{ g} = 64 \text{ g} \]

Thus, the mass of dioxygen (O₂) in the reactants is 64 g.