According to the Law of Conservation of Mass, if 88 g of carbon dioxide ( CO2 ) is produced in a reaction between oxygen (O) and 24 g of carbon (C), what is the mass of dioxygen ( O2 ) in the reactants?(1 point)

Question

Responses

32 g
32 g

24 g
24 g

104 g
104 g

64 g

Answer 1

To determine the mass of dioxygen (O₂) in the reactants based on the Law of Conservation of Mass, we can use the following principle: the mass of the reactants equals the mass of the products.

We know that:

• The mass of carbon (C) used is 24 g.
• The mass of carbon dioxide (CO₂) produced is 88 g.

According to the Law of Conservation of Mass: \[ \text{Mass of reactants} = \text{Mass of products} \]

Let \( m_{O2} \) be the mass of dioxygen (O₂) reacted. According to the equation: \[ 24 , \text{g (C)} + m_{O2} = 88 , \text{g (CO2)} \]

Now, solving for \( m_{O2} \): \[ m_{O2} = 88 , \text{g} - 24 , \text{g} \] \[ m_{O2} = 64 , \text{g} \]

Therefore, the mass of dioxygen (O₂) in the reactants is 64 g.