According to the Law of Conservation of Mass, if 88 g of carbon dioxide (CO2

) is produced in a reaction between oxygen (O) and 24 g of carbon (C), what is the mass of dioxygen (O2
) in the reactants?(1 point)
Responses

24 g
24 g

104 g
104 g

64 g
64 g

32 g

1 answer

According to the Law of Conservation of Mass, the total mass of the reactants must equal the total mass of the products.

In this case, the mass of carbon (C) used in the reaction is 24 g, and the mass of carbon dioxide (CO2) produced is 88 g.

To find the mass of dioxygen (O2) in the reactants, you can set up the equation:

Mass of reactants = Mass of products

Let \( m \) be the mass of dioxygen (O2):

\[ m + 24 , \text{g (mass of carbon)} = 88 , \text{g (mass of CO2)} \]

Solving for \( m \):

\[ m = 88 , \text{g} - 24 , \text{g} = 64 , \text{g} \]

Therefore, the mass of dioxygen (O2) in the reactants is 64 g.