A tennis ball is struck and departs from the racket horizontally with a speed of 29.1 m/s. The ball hits the court at a horizontal distance of 19.0 from the racket. How far above the court is the tennis ball when it leaves the racket?

Answer 1

time = distance/speed
t = 19m / 29.1m/s = .653s

So, how far does it fall in .653 seconds?

Answer 2

2.089m