A tennis ball is struck and departs from the racket horizontally with a speed of 26.9 m/s. The ball hits the court at a horizontal distance of 18.1 from the racket. How far above the court is the tennis ball when it leaves the racket?

Answer 1

d = V*T.

d = 26.9 * T = 18.1 m
T = 0.67 s.

h = 0.5g*t^2 = 4.9*(0.67)^2 = 2.22 m.