As a tennis ball is struck, it departs from the racket horizontally with a speed of 27.1 m/s. The ball hits the court at a horizontal distance of 20.0 m from the racket. How far above the court is the tennis ball when it leaves the racket

Answer 1

Dx = Vx * Tf = 20 m.
27.1 * Tf = 20
Tf = 0.738 s. = Fall time.

h = Yo*Tf + 0.5g*Tf^2
h = 0 + 4.9*0.738^2 = 2.67 m.