A tennis ball is struck and departs from the racket horizontally with a speed of 27.7 m/s. The ball hits the court at a horizontal distance of 20.6 m from the racket. How far above the court is the tennis ball when it leaves the racket?

Answer 1

Dx = Vx * Tf = 20.6 m.
27.7 * Tf = 20.6
Tf = 0.744 = Fall time.

h = 0.5g*Tf^2
g = +9.8 m/s^2
Solve for h.