The acceleration rate is
a = 11.5154/5.59 = 2.06 m/s^2
Displacement at t = 4.15337s =
(1/2) a t^2 = 17.77 m
A subway train starting from rest leaves a
station with a constant acceleration. At the end of 5.59 s, it is moving at 11.5154 m/s.
What is the train’s displacement in the first 4.15337 s of motion?
Answer in units of m
1 answer
1 answer