A subway train starting from rest leaves a station with a constant acceleration. At the end of 5.24 s, it is moving at 13.4144 m/s.

Question

What is the train’s displacement in the first 3.42696 s of motion?

Answer 1

v = at
13.4144 = 5.24a
a = 2.56

s = 1/2 at^2
s = .5 * 2.56 * 3.42696^2
s = 15.032390197

since you seem to like decimal places! :-)