a = (Vf-Vo)/t,
a = (13.4144-0)/5.24 = 2.56 m/s^2.
D = Vo*t + 0.5a*t^2,
D = 0 + 1.28*(3.42696)^2 = 15.03 m.
A subway train starting from rest leaves a station with a constant acceleration. At the end of 5.24 s, it is moving at 13.4144 m/s.
What is the train’s displacement in the first 3.42696 s of motion?
1 answer
1 answer