A student is skateboarding down a ramp that is 7.06 m long and inclined at 29.0° with respect to the horizontal. The initial speed of the skateboarder at the top of the ramp is 4.03 m/s. Neglect friction and find the speed at the bottom of the ramp.

Answer 1

h = L*sin A = 7.06*sin29 = 3.42 m.

V^2 = Vo^2 + 2g*h = 4.03^2 + 19.6*3.42 = 83.3
V = 9.13 m/s.