A student is skateboarding down a ramp that is 8.33 m long and inclined at 24.5° with respect to the horizontal. The initial speed of the skateboarder at the top of the ramp is 4.12 m/s. Neglect friction and find the speed at the bottom of the ramp.

Answer 1

h = L*sin A = 8.33*sin 24.5 = 3.45 m.

V^2 = Vo^2 + 2g*h
V^2 = 4.12^2 + 19.6*3.45 =
Solve for V.