A student is skateboarding down a ramp that is 5.9 m long and inclined at 14° with respect to the horizontal. The initial speed of the skateboarder at the top of the ramp is 2.5 m/s. Neglect friction and find the speed at the bottom of the ramp.

Answer 1

h = 5.9*sin14 = 1.43 m. = ht. of ramp.

V^2 = Vo^2 + 2g*h.
V^2 = 2.5 + 19.6*1.43 = 30.53,
V = 5.53 m/s.