A student is skateboarding down a ramp that is 5.5 m long and inclined at 19° with respect to the horizontal. The initial speed of the skateboarder at the top of the ramp is 2.9 m/s. Neglect friction and find the speed at the bottom of the ramp.

Answer 1

Apply conservation of energy. Neglect the rotational kinetic energy of the wheels, which will make a small difference since the wheels weigh much less than the skateboarder.

(M/2)[V2^2 - V1^2] = M g deltaH
= M g *5.5 sin 19

V1 = 2.9 m/s

Cancel the M's and solve for V2, the final velocity.

V2^2 - (2.9)^2 = 2*9.81*1.791 = 35.13
V2^2 = 35.13 + 8.41
V2 = 6.60 m/s

Answer 2

thank you

Answer 3

where did you get 1.791 from