h = 6.52/sin 19.8
loss of potential E = m g h
(1/2) m v^2 = m g h + (1/2) m (2.24)^2
m cancels
v^2 = 2 g h + 2.24^2
A student is skateboarding down a ramp that is 6.52 m long and inclined at 19.8 degrees with respect to the horizontal. The initial speed of the skateboarder at the top of the ramp 2.24 m/s. Neglect friction and find the speed at the bottom of the ramp in m/s.
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