A student is skateboarding down a ramp that is 6.52 m long and inclined at 19.8 degrees with respect to the horizontal. The initial speed of the skateboarder at the top of the ramp 2.24 m/s. Neglect friction and find the speed at the bottom of the ramp in m/s.

Answer 1

h = 6.52/sin 19.8

loss of potential E = m g h

(1/2) m v^2 = m g h + (1/2) m (2.24)^2
m cancels

v^2 = 2 g h + 2.24^2