A student is skateboarding down a ramp that is 6.03 m long and inclined at 21.5° with respect to the horizontal. The initial speed of the skateboarder at the top of the ramp is 4.87 m/s. Neglect friction and find the speed at the bottom of the ramp.

Answer 1

h = 6.03*sin21.5 = 2.21 m.

V^2 = Vo^2 + 2g*h = 4.87^2 + 19.6*2.21
V = Final velocity
Vo = 4.87 m/s
g = 9.8 m/s^2
Solve for V.