A steel bar of length L=2 m, with modulus E=200 GPa and constant cross sectional area A=200 mm2 is constrained between two walls at its two ends A and B. A distributed axial load, fx(x)=−p0(1−3x2L), with p0=200 kN/m, is applied to the bar only in the 0≤x≤23L section (no load is applied on right third of the bar).
2 answers
Find a symbolic expression for the axial force in the bar, N(x), in terms of p0,L, and x for 0≤x≤23L & for 2L3≤x≤L:
For for 2L/3 ≤ x ≤ L:
N(x) = p_0*2*L/27
u(x) = p_0*2*L/(27*E*A)*(x-L)
N(x) = p_0*2*L/27
u(x) = p_0*2*L/(27*E*A)*(x-L)
10 answers