Question

A steel bar of length L=2 m, with modulus E=200 GPa and constant cross sectional area A=200 mm2 is constrained between two walls at its two ends A and B. A distributed axial load, fx(x)=−p0(1−3x2L), with p0=200 kN/m, is applied to the bar only in the 0≤x≤23L section (no load is applied on right third of the bar).

Answer 1

The last questions:
0.79 mm
0.69 m

Anyone for the beggining questions please?

Answer 2

HW3_4B 0.49

Answer 3

Thanks Anonymous, do you have any of the HW3_3a, b, c, and d?

Answer 4

H_W3_4A 2.66

Answer 5

Thanks Pa!
Anyone for HW3_a, b, c,d?

Answer 6

HW3_2A for 2L/3≤x≤L: (p_0*2*L/27)

Answer 7

For for 2L/3 ≤ x ≤ L:
N(x) = p_0*2*L/27
u(x) = p_0*2*L/(27*E*A)*(x-L)

Anybody for the fist part (0 ≤ x ≤ 2L/3)

Answer 8

for (0 ≤ x ≤ 2L/3)

N(x)=(2*p_0*L)/27-p_0*(L/3-x+(3*x^2)/(4*L))

u(x)=(2*p_0*L*x)/(27*E*A)-p_0/(E*A)*((L*x)/3-x^2/2+x^3/(4*L))

Answer 9

HW3_4B
0.49

Answer 10

The last questions:
0.79 mm
0.7 m