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Hello! can someone help me how to solve this problem in MATLAB?
SHAFT SUBJECTED TO SINUSOIDAL DISTRIBUTED TORQUE Circular shaft
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Hello! can someone help me how to solve this problem in MATLAB?
SHAFT SUBJECTED TO SINUSOIDAL DISTRIBUTED TORQUE Circular shaft
0 answers
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Mary wants to throw a can straight up into the air and then hit it with a second can. She wants the collision to occur at height
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The truss structure ABCD is loaded with a concentrated force P = 2 kN applied at a 45° angle at joint D as indicated in the
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Answers (37)
HW7_3_2 part 2 0.5 part 3 0.05
HW7_3_2 part 2 0.5 part 3 0.05
HW7_3_2 part 2 0.5 part 3 0.05
HW 7_2_2 576 -576 281.33 -281.33 HW 7_3_1 -P*x
HW 7_2_2 576 -576 281.33 -281.33 HW 7_3_1 -P*x
HW 7_2_2 576 -576 281.33 -281.33 HW 7_3_1 -P*x
HW 7_3_1 -P*x (P capital)
7.1B1 Mmax- =-8000
HW7_3_1 PART 2 -P*x+P*(x-L_1)*(L_1+L_2)/L_2
HW7_3_1 PART 2 -P*x+P*(x-L_1)*(L_1+L_2)/L_2
HW7_1A_1 P*(1-a/(a+b))*x -(a/(a+b))*P*x+P*a HW7_1A_2 -(a/(a+b))*P*a+P*a a HW7_1A_3 2
HW7_1A_1 P*(1-a/(a+b))*x -(a/(a+b))*P*x+P*a HW7_1A_2 -(a/(a+b))*P*a+P*a a HW7_1A_3 2
HW7_1A_1 P*(1-a/(a+b))*x -(a/(a+b))*P*x+P*a HW7_1A_2 -(a/(a+b))*P*a+P*a a HW7_1A_3 2
HW7_1A_1 P*(1-a/(a+b))*x -(a/(a+b))*P*x+P*a HW7_1A_2 -(a/(a+b))*P*a+P*a a HW7_1A_3 2
HW7_1A_1 P*(1-a/(a+b))*x -(a/(a+b))*P*x+P*a HW7_1A_2 -(a/(a+b))*P*a+P*a a HW7_1A_3 2
HW7_1B: BENDING MOMENT DIAGRAMS AND STRESSES, PART II Cantilever A,B left sup=A (wall) L=2L Mo=PL/3, at B=2L P at L
HW7_1A: BENDING MOMENT DIAGRAMS AND STRESSES Length, L= a+b Point load a=a Point load b=P
HW7_1A L.Sup = hinge R.Sup= roller
6_2C= -L^2*t_0/(8*pi*G_0*R^4)
6_1B (2*Q*L^2)/(G*pi*t*d_A^2*(L+x)^2)
6_3 = 8*phi_m*G*I_p/(L^2)
6_3 8*phi_m*G*I_p/(L^2)
6_2A= -t_0*x 6_2B= -t_0*(x^2-L^2)/(8*pi*G_0*R^4) 6_2C= -L^2*t_0/(8*pi*G_0*R^4) 6_2D= 5*t_0*L/(4*pi*R^3)
HW6_1A 2*d_A^3*pi*t*G/(3*L )
5.3 % DO NOT EDIT % % % % % % % % % % % % % % % % % % % % % % % % L=3; % in [m] t_0=8; % in [kN] x = linspace(0,L); % t_x=t_0*(L-x)/L; % in [kN.m] % DO NOT EDIT % % % % % % % % % % % % % % % % % % % % % % % % T =((t_0/L)*(L-x).^2)/2; % DO NOT EDIT % % % %
q1_2_1 400, 300, 700, 565.685 q1_2_2 -800, -300, 0, 700
you must type the numbers, curly N just to indicate where is aplied
-1,1,-0.7071,0,0,0 0,0,-0.7071,-1,0,0 0,-1,0,0,-0.7071,0 0,0,0,0,-0.7071,0 0,0,0,0,0.7071,-1 0,0,0,1,0.7071,0 1/sqrt(2) = 1/1.4142 = 0.7071
N_AB N_BC N_BE N_BD N_CD N_ED -1 1 -0,7071 0 0 0 0 0 -0,7071 -1 0 0 0 -1 0 0 -0,7071 0 0 0 0 0 -0,7071 0 0 0 0 0 0,7071 -1 0 0 0 1 0,7071 0 b 0 0 0 2 0 0 X = a\b N AB 4,000 N BC 2,000 N BE -2,828 N BD 2,000 N CD -2,828 N ED -2,000
4_2 part IIA RxA=-4, RyA=0 4_2 part IIB RxE=4, RyE=2
RxA= -4, sorry
4_2 part IIA RxA=4, RyA=0 4_2 part IIB RxE=4, RyE=2
4_2 part IIA RxA=4, RyA=0 4_2 part IIB RxE=4, RyE=2
1_A : -1.17, -1.17, 1.4142, 0.936, 2.35 1_B : -1.414, 0.702, 0.702 1_C:-4.13, -4.13,2.647,6.646
1_A : -1.17, -1.17, 1.4142, 0.936, 2.35 1_B : -1.414, 0.702, 0.702 1_C:-4.1, -4.13,2.647,6.646
1_A : -1.17, -1.17, 1.4142, 0.936, 2.35 1_B : -1.414, 0.702, 0.702
HW3_2A for 2L/3≤x≤L: (p_0*2*L/27)
