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0.8235
12 years ago
Symbolic expression for fx(x): 0<x<L/2 : rho_1*g*A L/2<x<L : rho_2*g*A Symbolic expression for N(x): 0<x<L/2 : rho_2*g*A*L/2 L/2<x<L : rho_2*g*A*(L-x)
12 years ago
u1 = -a*L*x1; u2 = 2*a*(x2.^2-L*x2);
12 years ago
N1 = -3*a*L*A*E+0*x1; N2 = 6*a*A*E*(2*x2-L);
12 years ago
fx1 = 0 + 0*x1; fx2 = -12*a*A*E + 0*x2;
12 years ago
Fx = -3*a*L*A*E x = L/2
12 years ago
Rx(B) = 3*a*A*E*L Rx(C) = 6*a*A*E*L
12 years ago
For for 2L/3 ≤ x ≤ L: N(x) = p_0*2*L/27 u(x) = p_0*2*L/(27*E*A)*(x-L)
12 years ago
For for 2L/3 ≤ x ≤ L: N(x) = p_0*2*L/27 u(x) = p_0*2*L/(27*E*A)*(x-L) Anybody for the fist part (0 ≤ x ≤ 2L/3)
12 years ago
308
12 years ago
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