Pa

H_W3_4A 2.66

HW3_1A: -86.8

-86.8 MPa

-86.8 MPa

HW3_2A N(x)= (2*p_0*L)/27-p_0*(L/3-x+(3*x^2)/(4*L)) N(x)=(2*p_0*L)/27

HW3_2B 0<x<(2/3)L (2*p_0*L*x)/(27*E*A)-p_0/(E*A)*((L*x)/3-x^2/2+x^3/(4*L))

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