A spring sketch by 6cm when supporting a load of 15N? By how much would it stretch when supporting a load of 5Kg

Answer 1

F = k x
15 = k * 6
k = 15/6
5 = (15/6) x
x = 5 * (6/15 ) = 2 cm

Answer 2

Mg = 5*9.8 = 49 N.
15/6 = 49/x
X = 19.6 cm.

Answer 3

Please any other way to calculate it

Answer 4

15000kg-6

Answer 5

Ratio way
15÷5=6÷x
Cross multiplication
15x=30
x=30÷15
x=2

Answer 6

can yall explain what ur doing step by step in simpler terms