A spring stretches by 6cm when supporting a load of 15N ,what load would make the spring extend by 25mm
6 answers
one posting will suffice. Repeats just waste your time and ours.
I am asking the same
I am asking the same
Yeah wat
6cm=15N
2.5cm=?
2.5cm*15N/6cm
ans=6.25N
2.5cm=?
2.5cm*15N/6cm
ans=6.25N
This answer is incorrect.
To solve this problem, we can use the equation:
F = kx
where F is the force applied to the spring, x is the displacement of the spring from its resting position, and k is the spring constant.
We can rearrange this equation to solve for k:
k = F/x
We know that when the spring is supporting a load of 15N, it stretches by 6cm. So we can plug these values into the equation:
k = 15N / 0.06m = 250 N/m
Now we can use this value of k to find the force required to extend the spring by 25mm:
F = kx = (250 N/m) * 0.025m = 6.25N
Therefore, a load of 6.25N would make the spring extend by 25mm.
To solve this problem, we can use the equation:
F = kx
where F is the force applied to the spring, x is the displacement of the spring from its resting position, and k is the spring constant.
We can rearrange this equation to solve for k:
k = F/x
We know that when the spring is supporting a load of 15N, it stretches by 6cm. So we can plug these values into the equation:
k = 15N / 0.06m = 250 N/m
Now we can use this value of k to find the force required to extend the spring by 25mm:
F = kx = (250 N/m) * 0.025m = 6.25N
Therefore, a load of 6.25N would make the spring extend by 25mm.