A Spring streches by 6 cm when supporting a load of 15 N.How much would it stretch when supporting a load of 5 kg
5 answers
15-5=10
x / 6 = (5 g) / 15 ... x = 2 g ... cm
M*g = 5*9.8 = 49 N.
15/6 = 49/x
X =
15/6 = 49/x
X =
What load would make the spring extend by 25mm.show working
We are given:
Extension, E = 25 mm = 0.025 m
Load, F = ?
We know that the extension of a spring is directly proportional to the load applied to it. This can be expressed as:
F ∝ E
Or
F = k*E ----(1)
where k is the spring constant.
Now, we can rearrange equation (1) to find k:
k = F/E ----(2)
We can use the given information that the spring extends by 6 cm when a load of 15 N is applied to find k:
k = F/E = 15 N / 0.06 m = 250 N/m
Now, we can use equation (1) to find the load that would make the spring extend by 25 mm:
F = k*E = (250 N/m)*(0.025 m) = 6.25 N
Therefore, a load of 6.25 N would make the spring extend by 25 mm.
Extension, E = 25 mm = 0.025 m
Load, F = ?
We know that the extension of a spring is directly proportional to the load applied to it. This can be expressed as:
F ∝ E
Or
F = k*E ----(1)
where k is the spring constant.
Now, we can rearrange equation (1) to find k:
k = F/E ----(2)
We can use the given information that the spring extends by 6 cm when a load of 15 N is applied to find k:
k = F/E = 15 N / 0.06 m = 250 N/m
Now, we can use equation (1) to find the load that would make the spring extend by 25 mm:
F = k*E = (250 N/m)*(0.025 m) = 6.25 N
Therefore, a load of 6.25 N would make the spring extend by 25 mm.
6 answers