Question

A solution of potassium phosphate is mixed with a solution of calcium acetate.

I am supposed to write a net ionic equation. Doesn't need to be balanced.
Here is what I did:

K3PO4(aq) + Ca(C2H3O2)2 --> KC2H3O2 + Ca3PO4

3K+ + PO4-3 + Ca+2 2(C2H3O2-) --> K+ + C2H3O2 + 3Ca+2 + PO4-3

2K+ + Ca+2 + C2H3O2 --> 2Ca+2

Answer 1

K3PO4(aq) + Ca(C2H3O2)2 --> KC2H3O2<b>(aq)</b> + Ca3<b>(</b>PO4<b>)2</b> <b>See Ca3(PO4)2. See (aq) I inserted above.</b>

3K+ + PO4-3 + Ca+2 <b>+</b> 2(C2H3O2-) --> K+ + C2H3O2 + 3Ca+2 + PO4-3
<b>See the + sign I inserted above in bold. Then, Ca3(PO4)2 is the correct formula for calcium phosphate. Finally, Ca3(PO4)2 is insoluble and should be wirtten as a solid.</b>

2K+ + Ca+2 + C2H3O2 --> 2Ca+2

Answer 2

Ok, thanks I had that written on the paper, but I forgot to type it. Also, descriptive subscripts are not required for this assignment so I didn't bother with them.

Thanks DrBob222!

Answer 3

net ionic equation is
PO4^-3(aq) + Ca^+2(aq) ==> Ca3(PO4)2(s)