Question

Potassium Chloride 3:4 solution 30ml. How many milliliters of a potassium 1:20 solution and 4:5 solution do you need to prepare the order?

Answer 1

How do you define a 3:4 solution of KCl?

Answer 2

How do you figure out this problem

Answer 3

This is a two part question in which requires the use of the Alligation calculation method.
1) you will need to change the 3:4, 1:20, and 4:5 into their percentage parts.
How you do this is by simply dividing (remember 3:4 is the same as the fraction 3/4) so 3 divided by 4 gives you 75%.
2) Next you will need to plug in these number to the Alligation calculation table (this tic-tac-toe table). 80% top left corner, 5% in the bottom left corner. 80-5= 75 therefore, 75% goes into the middle square which is your desired does. 80-75= 5 so 5 parts goes into the bottom right corner. 75-5=70 therefore, 70parts goes into the top right corner. 70+5=75 which goes into the square between 70 and 5, to represent the total number of parts.
3) Now you just need to apply the numbers acquired into the next formula. so, the answer of mL required for the 4:5 (80%) is as follows; 70/75=0.93*30=28 mL (this is ONLY half of the answer.
1:20 (5%) 5/75=0.067*30=2 mL.
4) You will need 28 mL of the 4:5 solution and 2 mL of the 1:20 solution to prepare the order.