Asked by Anonymous
If 36 g of potassium chloride are dissolved in 100mL of water at 40 C to form a saturated solution, how many grams of potassium chloride would be required to form a saturated solution in 250 mL of water at the same temperature?
Answers
Answered by
eloise
250mL/100mL=1.5
36g * 2.5=90g
90 grams KCl (potassium chloride) will be needed to make a saturated solution in 250 mL of water at 40 degrees C.
36g * 2.5=90g
90 grams KCl (potassium chloride) will be needed to make a saturated solution in 250 mL of water at 40 degrees C.
Answered by
Jenna
That's really easy.
you do 250/100 which is 2.5
then, you multiply that to the mass of KCl and get 90g like what the other person said.
you do 250/100 which is 2.5
then, you multiply that to the mass of KCl and get 90g like what the other person said.
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