If 36 g of potassium chloride are dissolved in 100mL of water at 40 C to form a saturated solution, how many grams of potassium chloride would be required to form a saturated solution in 250 mL of water at the same temperature?

Answer 1

250mL/100mL=1.5
36g * 2.5=90g

90 grams KCl (potassium chloride) will be needed to make a saturated solution in 250 mL of water at 40 degrees C.

Answer 2

That's really easy.
you do 250/100 which is 2.5
then, you multiply that to the mass of KCl and get 90g like what the other person said.