Question

A 500 mL potassium chloride solution was prepared by dissolving
potassium chloride in distilled water. 25.0 mL of the solution was
titrated with 0.300 M silver nitrate solution. 28.90 mL of silver
nitrate solution was required to reach the end point in the titration.
What is the number of moles of potassium chloride present in the
500.0 mL solution?

𝐾𝐶𝑙(𝑎𝑞) + 𝐴𝑔𝑁𝑂3(𝑎𝑞) → 𝐴𝑔𝐶𝑙(𝑠) + 𝐾𝑁𝑂3(𝑎𝑞)

Answer 1

moles silver nitrate=.3*.0288
moles KCL= moles silver nitrate=.0864
now number moleKCl in 500ml= .0964*500/25=...