Answers by visitors named: Prince
read the text book, chemistry by raymond chang chapter 14
How do I know that is the price of the apple instead of the pear???
OOOOkkay! Now I got it! The amount of pears stayed the same. Thanks!
B: When they struggle with body changes.
Its B
1 answer
cross multiply and you will get something like this
2.5 X x = 0.5 X 1.25
which the answer will be
2.5x = 0.625
because we are finding for x so divide both sides by 2.5 so that x can stand alone. so 0.5x over(divided by) 2.5 and 0.625 over(divided by) 2.5.
(note: we are finding for x).
so the answer will now be
x=0.25
Human right violation of xenophobia
People will live in fear
Make six suggestions on how to combat the violation or discrimination
120
i think it is just a hard Q.
A car moving with the velocity of 20m/s at 30 to the horizontal, what is the components of the velocity along the horizontal
Yes fadf I have seen a crap load of her post from 2001 thru 2017 I am shocked she is even alive because of how much she does this but I wonder if she some kinda bot lol well I gtg
I am officially going down in history for this reply.
Why a study on environmental issues that causes ill health a necessity
its on the website studies weekly your welcome
If 465 cm^3 of sulphur(IV) oxide, can diffuse through porous partition in 30 seconds, how long
will (a) an equal volume, (b) 620 cm^3 of hydrogen sulphide take to diffuse through the same
partition
Solution
To answer this question we should use Graham’s Law: rate of effusion for a gas is inversely
proportional to the square root of it’s molar mass:
Rate of effusion = 1/M.
For two gases:
Rate A/Rate B = MB/MA.
a) We have: V(SO2)= 0.465 dm3
t (SO2) = 30 s
V(H2S)= 0.465 dm3
Rate SO2 = n (SO2)/t;
n(SO2)= V/Vm; Vm =22.4 dm3
/mol;
n(SO2) = 0.465 dm3
/22.4 dm3
/mol =0.021 mol;
rate SO2= 0.021 mol/30 s =6.9210-4 mol/s.
Find rate H2S from Graham’s Law:
6.9210-4
/rate H2S = 34.09/64.07,
where M(H2S)=1.012+32.07=34.09 (g/mol), M(SO2) = 32.07+16.002 =64.07 (g/mol);
rate H2S = 9.4910-4 mol/s.
Find chemical amount of H2S:
n(H2S)= V/Vm; Vm =22.4 dm3
/mol;
n(H2S) = 0.465 dm3
/22.4 dm3
/mol =0.021 mol.
Rate H2S = n(H2S)/t;
9.4910-4 mol/s =0.021 mol/t;
t= 21.87 s.
b) We have: V(SO2)= 0.465 dm3
t(SO2)= 30s
V(H2S) = 0.620 dm3
Rate SO2 = n (SO2)/t;
n(SO2)= V/Vm; Vm =22.4 dm3
/mol;
n(SO2) = 0.465 dm3
/22.4 dm3
/mol =0.021 mol;
rate SO2= 0.021mol/30 s =6.9210-4 mol/s.
Find rate H2S from Graham’s Law:
6.9210-4
/rate H2S = 34.09/64.07,
where M(H2S)=1.012+32.07=34.09 (g/mol), M(SO2) = 32.07+16.002 =64.07 (g/mol);rate H2S = 9.4910-4 mol/s.
Find chemical amount of H2S:
n(H2S)= V/Vm; Vm =22.4 dm3
/mol;
n(H2S) = 0.620 dm3
/22.4 dm3
/mol =0.0277 mol.
Rate H2S = n(H2S)/t;
9.4910-4 mol/s =0.0277 mol/t;
t= 29.19 s.
Answer: a) 21.87 s; b) 29.19 s
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The quality of the pens was not good.
in number 2, if you try it with 0.5 then 2 > 0 and 0.5 ≥ 0 then it is true? while if i try it on x = 0, 1/0 is undefined, and 0 ≥ 0 is true, therefore the biconditional statement is false?
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Prince
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Lack of employment
Bad Economy
Lack of infrastructural facilities
•Conflict, when well-managed, can be positive. If not, it may cause more harm.
•It may give conflicting parties an opportunity to vent their dissatisfaction. It will however remain a positive exercise only if the other party is willing to listen with an open mind.
•At times conflict may help parties to express feelings that they would not have expressed under circumstances. This also depends on how expressing of
one’s feelings will be perceived by the other
•Conflict may also create awareness of the other person’s feelings.
•It may help parties to become aware of their own shortcomings and may
help them to improve their relations towards others.
180°
English is the language of opportunity to teach
0.2
1.51×10^23
How many molecules of hydrogen
9 0 8 4 0 3
Greatest 1 digit number = 9
Least 1 digit number = 1
Least 2-digit number = 10
I need the answer
Evaluate 136.8 in standard form
Express 25cm as a fraction of 3m
How did you get the 4 in a + 4b = 13
Yes
25,4,2022
I will
what is dumb + dumb equal
45 kg/cm²
5.26
1. What are the mean median mode and range of the data set given the altitude of lakes in feet: -9,-36,-23,-8,-17,-52,-27 and -36
Answer: C -26; median=-25; mode=-36; range= 44
2. Given the data 21 13 13 37 13 23 25 15
Answer: B 37;20; 17.6
I promise I'll post the other questions later 👍✌
Only use these answers to see why you get them wrong okay i don't want people to cheat I just want them compare and see why their answers are wrong
I took the test last week and i got all of them correct!
So good luck!👍🍀