Asked by Carol
a 30.0 ml solution of potassium nitrate was diluted to 125 ml and 25 ml of this solution were then diluted to 150 ml. the concentration of the final solution is 0.00307 M. Calculate the concentration of the original solution.
Answers
Answered by
DrBob222
xM*(30/125)*(25/150) = 0.00307
Answered by
Sarah (C)
i do not know if this is right but this is how i would do it.
M1V 1=M2V2.
(0.00307 M) X (150ml)= (M2) X (30 ml)
and then you solve to get m2
M1V 1=M2V2.
(0.00307 M) X (150ml)= (M2) X (30 ml)
and then you solve to get m2
Answered by
DrBob222
Sarah's method will work if you do it TWICE; once for each dilution.
0.00307*150 = 25*c
c = ??
??*125 = 30c
c = xx.
You should arrive at the same answer either way.
0.00307*150 = 25*c
c = ??
??*125 = 30c
c = xx.
You should arrive at the same answer either way.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.