A solution of potassium permanganate (KMnO4) was standardised by titrating with 0.20 g of Na2C2O4 dissolved in 50 cm3 of acidified water. The endpoint was reached after 23.10 cm3 of solution had been added. Calculate the molar concentration of KMnO4 in the solution.

Answer 1

1. Write and balance the equation.
2MnO4^- + 5C2O4^2- + ? ==> 2Mn^2+ + 10CO2 +?
I didn't finish the entire equation (that is I omitted the H^+, electrons, and H2O) BUT I balanced the redox part and that's all you need.

2. mols Na2C2O4 = grams/molar mass = ?

3. Using the coefficients in the balanced equation, convert mols C2O4^2- to mols MnO4^-. That's ?mols Na2C2O4 x (2 mols KMnO4/5 mols Na2C2O4) = ?

4. Then M KMnO4 = mols KMnO4/L KMnO4