A school class is selling cookies for a fundraiser. The class has made 120 cookies to sell, and the supplies to make the cookies cost $22. The class wants to make at least $50 from selling cookies.

Question

Which inequality should be used to determine the possible prices (p) the class can sell the cookies for to reach its goal?

(1 point)
Responses

120p−22≥50

120p−22>50

120p−22<50

120p−22≤50

Question 2
(1 point)
The class should sell each cookie for at least, exactly, less than, at most or greater than?
$0.60.

Answer 1

To determine the appropriate inequality for the class selling cookies, we need to represent the total earnings from selling cookies, taking into account their costs and their desired profit.

The class makes \(120\) cookies and sells each for a price \(p\). Therefore, the total revenue from selling the cookies is \(120p\). The cost of supplies to make the cookies is \(22\), so the profit from selling the cookies is given by:

\[ \text{Profit} = \text{Revenue} - \text{Cost} = 120p - 22 \]

The class wants to make at least \(50\) dollars in profit. Therefore, we set up the inequality:

\[ 120p - 22 \geq 50 \]

So, the correct inequality is:

120p−22≥50

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For question 2, we want to find the minimum price per cookie that the class must charge to reach their goal.

From the inequality \(120p - 22 \geq 50\), we can solve for \(p\):

1. Add \(22\) to both sides: \[ 120p \geq 72 \]

2. Divide by \(120\): \[ p \geq \frac{72}{120} \]

3. Simplifying \(\frac{72}{120}\): \[ p \geq 0.60 \]

Thus, the class should sell each cookie for at least $0.60.