11s+4c = 93
9s+2c = 71
The school is selling tickets the first day the school sold 11 senior tickets and 4 child tickets a total of $93. the school sold $71 worth of tickets the second day 9 senior tickets and 2 child tickets find the price of a senior ticket and the price of a child ticket.
4 answers
6.50 s 5.00 k
Steve I still don't no the answer to this question please help!
11s+4c = 93
9s+2c = 71
double the 2nd equation:
11s+4c = 93
18s+4c = 142
subtract the top from the bottom:
7s = 49
s = 7
11s+4c=93, so
77+4c = 93
4c = 16
c = 4
So, they sold 7 senior and 4 child tickets
9s+2c = 71
double the 2nd equation:
11s+4c = 93
18s+4c = 142
subtract the top from the bottom:
7s = 49
s = 7
11s+4c=93, so
77+4c = 93
4c = 16
c = 4
So, they sold 7 senior and 4 child tickets