A girl walks 7km on a bearing of 030° she then changes direction and walks 8km on a bearing of 120° find the distance and bearing from her starting point
2 answers
Pls solve it
Did you make a diagram of the triangle?
I have mine showing sides of 7 and 8 with a 90° angle between them.
So it is just using Pythagoras
d^2 = 7^2 + 8^2 = 113
d = √113 = appr 10.63 km
For the angle of the triangle at the starting point:
tanθ = 8/7 = ....
θ = appr 48.8°
bearing from start = 48.8 + 30° = 78.8°
I have mine showing sides of 7 and 8 with a 90° angle between them.
So it is just using Pythagoras
d^2 = 7^2 + 8^2 = 113
d = √113 = appr 10.63 km
For the angle of the triangle at the starting point:
tanθ = 8/7 = ....
θ = appr 48.8°
bearing from start = 48.8 + 30° = 78.8°
4 answers