A girl starts from point A and walks 285m to B on a bearing of 078.She then walks due south to a point C which is 307m from A. What is the bearing of A from C,and what is {BC}?

Question

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Anonymous · Accepted Answer

Why can't this solutionr be written properly

Steve · Answer

the girls walks on a heading, not a bearing.

B's bearing from A is 78°

If A is at (0,0), then B is at (279,59)

If we mark point D due east of A, on the line BC, then D is at (279,0)

Now, if angle DAC is θ, then

cosθ = 279/307
θ = 25°

So, A's bearing from C is 270+25 = 295°

BC = 59+279sin25° = 177m

Anonymous · Answer

Why can't this solutions be written properly

Oluchi · Answer

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