A girl starts at A and walks 2km south to B.she then walks 3km west to C.find the distance and bearing of C from A.
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please answer my question
draw the diagram. You have a right triangle with legs 2 and 3, so the hypotenuse √13
So, the distance AC is √13
the bearing of C from A is 180+arctan(3/2) = 236.3°
So, the distance AC is √13
the bearing of C from A is 180+arctan(3/2) = 236.3°
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The diagram of the question
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