Asked by Moyosoreoluwa
                A boy walks 10 m due west and 10m due south.What is the displacement.[2]a girl walks 12m northwards,5m eastwards and 7m southwards.Calculate her total displacement[3]a man walks 5km south and 3km in the direction 60 degree west of south.Calculate his distance from starting point.
            
            
        Answers
                    Answered by
            Steve
            
    these all just use the Pythagorean Theorem, or the distance formula, which is the same.
Just figure out the final location, and then use the formula.
For #1,
(0,0) -> (-10,0) -> (-10,-10)
distance is √(10^2+10^2) = 14.1
    
Just figure out the final location, and then use the formula.
For #1,
(0,0) -> (-10,0) -> (-10,-10)
distance is √(10^2+10^2) = 14.1
                    Answered by
            Manu Danso Dennis 
            
    Using Pythagoras theorem the answer is 14.1 for question 1
    
                    Answered by
            henry2,
            
    2.  Disp. = 12i + 5 - 7i = 5 + 5i = 7.07m[45o].
3. All angles are measured CW from +y-axis.
Disp. = 5[180o] + 3[240o].
X = 5*sin180 + 3*sin240 = -2.60 km.
Y = 5*Cos180 + 3*Cos240 = -6.5 km.
Disp. = -2.60 + (-6.5)I = 7.0[22o] W. of S. = 7.0km[202o] CW.
    
3. All angles are measured CW from +y-axis.
Disp. = 5[180o] + 3[240o].
X = 5*sin180 + 3*sin240 = -2.60 km.
Y = 5*Cos180 + 3*Cos240 = -6.5 km.
Disp. = -2.60 + (-6.5)I = 7.0[22o] W. of S. = 7.0km[202o] CW.
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