Asked by tobey
adaobi walks 2km due west and 2km due south calculate the displacement of the girl
Answers
Answered by
Henry
X = -2 km.
Y = -2 km.
D^2 = X^2 + Y^2,
D^2 = (-2)^2 + (-2)^2 = 8,
D = 2.83 km.
tanA = Y/X = -2 / -2 = 1.
Ar = 45 Deg. = Reference angle.
A = 45 + 180 = 225 Deg., Q3.
D = 2.83 km @ 225 Deg.
Y = -2 km.
D^2 = X^2 + Y^2,
D^2 = (-2)^2 + (-2)^2 = 8,
D = 2.83 km.
tanA = Y/X = -2 / -2 = 1.
Ar = 45 Deg. = Reference angle.
A = 45 + 180 = 225 Deg., Q3.
D = 2.83 km @ 225 Deg.
Answered by
David
23
Answered by
chinma
thanks
Answered by
Bello Ameerah Oluwadamilola
X=v×t
C^2=(2)^2+(2)^2
C^2=4+4
C^2=8
Tan=opp÷adj=2÷2=1
Tan-11=45
X=2Square root 2
=45dues
C^2=(2)^2+(2)^2
C^2=4+4
C^2=8
Tan=opp÷adj=2÷2=1
Tan-11=45
X=2Square root 2
=45dues
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