A dock worker applies a constant horizontal force of 80.0N to a block of ice on a smooth horizontal floor. The frictional force is negligible. the block starts from rest and moves 11.0 m in the first 5.00s what is the mass of the block of ice?

Answer 1

Calculate a from
S=ut + at²/2
where
S=11 m
u=0
t=5 s

From F=ma
where
F=80 N
a= as calculated above
you would be able to find m.

Answer 2

F = m a
a = 80/m
v = a t = (80/m) t
d = (1/2) a t^2 = (1/2)(80/m) t^2
11 = (1/2) (80/m) (25)
22 m = 80 * 25
I guess you can take it from there.

Answer 3

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